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prefer-numeric-literals

Disallow parseInt() and Number.parseInt() in favor of binary, octal, and hexadecimal literals

🔧 Fixable

Some problems reported by this rule are automatically fixable by the --fix command line option

❄️ Frozen

This rule is currently frozen and is not accepting changes.

The parseInt() and Number.parseInt() functions can be used to turn binary, octal, and hexadecimal strings into integers. As binary, octal, and hexadecimal literals are supported in ES6, this rule encourages use of those numeric literals instead of parseInt() or Number.parseInt().

0b111110111 === 503;
0o767 === 503;

Rule Details

This rule disallows calls to parseInt() or Number.parseInt() if called with two arguments: a string; and a radix option of 2 (binary), 8 (octal), or 16 (hexadecimal).

Examples of incorrect code for this rule:

Open in Playground
/*eslint prefer-numeric-literals: "error"*/

parseInt("111110111", 2) === 503;
parseInt(`111110111`, 2) === 503;
parseInt("767", 8) === 503;
parseInt("1F7", 16) === 503;
Number.parseInt("111110111", 2) === 503;
Number.parseInt("767", 8) === 503;
Number.parseInt("1F7", 16) === 503;

Examples of correct code for this rule:

Open in Playground
/*eslint prefer-numeric-literals: "error"*/

parseInt(1);
parseInt(1, 3);
Number.parseInt(1);
Number.parseInt(1, 3);

0b111110111 === 503;
0o767 === 503;
0x1F7 === 503;

a[parseInt](1,2);

parseInt(foo);
parseInt(foo, 2);
Number.parseInt(foo);
Number.parseInt(foo, 2);

When Not To Use It

If you want to allow use of parseInt() or Number.parseInt() for binary, octal, or hexadecimal integers, or if you are not using ES6 (because binary and octal literals are not supported in ES5 and below), you may wish to disable this rule.

Compatibility

Version

This rule was introduced in ESLint v3.5.0.

Resources

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